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ok guys. we will be pulling some Div1 antique and a classic class we devised '59-'80 field tractors. the breakdown is every 1000lbs. so a distance measurement is not really fair putting a 5100lb tractor against a 5900lb tractor since these guys arnt moving weight. previously the sled we used had a way to measure the distance box travels on the sled and we had a formula for it.
(total inches + 42.4) + 2800 / tractor weight
however this year and hopefully in the future we have invited a self propelled sled to help us speed things up and free up a person as well as a pullback tractor. so, anyway, this new sled does not have a way to measure the distance the box moves up.
so i was wondering if something like this would work. its not a true % but does give a factor in which to rank the tractors. tractor ranks would only apply at each class.
(distance pulled in ft x large constant) / tractor weight. example i have been playing with using a 5000 lb tractor, 5500 and a 5999. all pulling 120 ft to show the rank and then pulling different distances.
(120x15000)/ 5000= 360 (120x15000)/ 5500= 327 (120x15000)/ 5999= 300 so all pulling the same distance the lightest tractor has the highest score. i can do the same deal pulling different distances and get a factor, but not sure if its accurate (120x15000)/ 5000= 360 (130x15000)/ 5500= 354 (140x15000)/ 5999= 350
so applied this way it shows the light tractor winning again even with the heavier guys going a little farther. what do you guys think?
last year I had the old formula in a spreadsheet on a laptop and it worked great. much easier than figuring each pull. would like to do something similliar this year but need a way to figure placing based off distance and weight.
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Me -C,U,UC,WC,WD45,190XT,TL-12,145T,HD6G,HD16,HD20
Dad- WD, D17D, D19D, RT100A, 7020, 7080,7580, 2-8550's, 2-S77, HD15
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